Changes between Initial Version and Version 1 of Ticket #28413, comment 2
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 04/27/21 08:25:13 (5 months ago)
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Ticket #28413, comment 2
initial v1 1 1 Replying to [comment:1 ghwbruns]: 2 > For the h^* vector o be welldefined, the polytope should have integral vertices. Otherwise there is no canonical choice for the denominator and, hence, the numerator of the Ehrhart series (as a rational function).2 > For the h^*^vector o be welldefined, the polytope should have integral vertices. Otherwise there is no canonical choice for the denominator and, hence, the numerator of the Ehrhart series (as a rational function). 3 3 > 4 4 > At least one should check that the denominator is a power of 1t.