Changes between Initial Version and Version 1 of Ticket #28413, comment 1
 Timestamp:
 04/27/21 08:24:59 (5 months ago)
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Ticket #28413, comment 1
initial v1 1 For the h^* vector o be welldefined, the polytope should have integral vertices. Otherwise there is no canonical choice for the denominator and, hence, the numerator of the Ehrhart series (as a rational function).1 For the h^*^vector o be welldefined, the polytope should have integral vertices. Otherwise there is no canonical choice for the denominator and, hence, the numerator of the Ehrhart series (as a rational function). 2 2 3 3 At least one should check that the denominator is a power of 1t.