Changes between Initial Version and Version 1 of Ticket #25477, comment 39
 Timestamp:
 06/05/18 15:53:51 (4 years ago)
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Ticket #25477, comment 39
initial v1 15 15 Given such a sequence {{{SGS = C1,C2,...,Ci}}}, {{{elements(SGS)}}} iterates over all elements in {{{Si}}}. This is done by recursively doing the computation for {{{C1,C2,..,C{i1} }}} and then yielding all elements in {{{S{i1} }}} multiplied with all elements in {{{S=Ci}}}. 16 16 17 {{{if not SGS}}} means that we have reached the trivial subgroup and {{{S = [()]}}}. So the first {{{for g in S: yield g}}} could be replaced with {{{yield S[0]}}}.