Changes between Initial Version and Version 1 of Ticket #25477, comment 39


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Timestamp:
06/05/18 15:53:51 (4 years ago)
Author:
stumpc5
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  • Ticket #25477, comment 39

    initial v1  
    1515Given such a sequence {{{SGS = C1,C2,...,Ci}}}, {{{elements(SGS)}}} iterates over all elements in {{{Si}}}. This is done by recursively doing the computation for {{{C1,C2,..,C{i-1} }}} and then yielding all elements in {{{S{i-1} }}} multiplied with all elements in {{{S=Ci}}}.
    1616
     17{{{if not SGS}}} means that we have reached the trivial subgroup and {{{S = [()]}}}. So the first {{{for g in S: yield g}}} could be replaced with {{{yield S[0]}}}.