Opened 5 years ago
Last modified 5 years ago
#19123 closed enhancement
LatticePoset: add is_vertically_decomposable — at Version 13
Reported by:  jmantysalo  Owned by:  

Priority:  major  Milestone:  sage7.0 
Component:  combinatorics  Keywords:  
Cc:  ncohen, tscrim, kdilks  Merged in:  
Authors:  Jori Mäntysalo  Reviewers:  
Report Upstream:  N/A  Work issues:  
Branch:  u/jmantysalo/vertically_decomposable (Commits)  Commit:  ca909a0c05fee489a071ff672b9f3b5392ba8158 
Dependencies:  Stopgaps: 
Description (last modified by )
This patch adds a function is_vertically_decomposable
to finite lattices.
For testing see https://oeis.org/A058800 ; for example
sum([1 for L in Posets(6) if L.is_lattice() and not LatticePoset(L).is_vertically_decomposable()])
returns 7 as it should.
Change History (13)
comment:1 Changed 5 years ago by
 Branch set to u/jmantysalo/vertically_decomposable
comment:2 Changed 5 years ago by
 Cc ncohen added
 Commit set to 0d472a68c9edf4ddea1404ff0cb6d2f508de55d0
 Status changed from new to needs_review
comment:3 followup: ↓ 4 Changed 5 years ago by
Sounds good, but don't you think it may be useful to *know* where the poset splits? Also, why is it only defined for lattices? The algorithm works in all cases.
I did not test it, but from the code's look I am not sure that it works for the chain of length 2, as the docstring indicates. Could you add a doctest for that?
Nathann
comment:4 in reply to: ↑ 3 ; followup: ↓ 5 Changed 5 years ago by
 Status changed from needs_review to needs_work
Replying to ncohen:
Sounds good, but don't you think it may be useful to *know* where the poset splits?
Yes, I think that will be usefull. For posets we have is_connected()
, connected_components()
and disjoint_union()
. I guess we should have is_vertically_decomposable()
, vertically_indecomposable_parts()
and vertical_sum()
for lattices.
There are of course other options, like having a function (this one, with an argument?) returning list of "decomposition elements". The user could then run interval()
on them to get parts.
Also, why is it only defined for lattices? The algorithm works in all cases.
How should it be defined on nonconnected posets? And I am not sure if this works with nonbounded posets; I thinked about bounded ones when writing this.
I did not test it, but from the code's look I am not sure that it works for the chain of length 2, as the docstring indicates. Could you add a doctest for that?
Arghs! You are right, of course. I forget the special case when writing the code. I'll correct it.
(Btw, this would be nice exercise of (totally unneeded) optimization. One should not need to look for all edged of Hasse diagram to see that a poset is indecomposable.)
comment:5 in reply to: ↑ 4 ; followup: ↓ 6 Changed 5 years ago by
There are of course other options, like having a function (this one, with an argument?) returning list of "decomposition elements".
+1 to that.
How should it be defined on nonconnected posets? And I am not sure if this works with nonbounded posets; I thinked about bounded ones when writing this.
Hmmm, okay okay... I attempted to write a definition, but indeed for nonlattices you have 1000 different cornercases, and th definition would be a mess.
(Btw, this would be nice exercise of (totally unneeded) optimization. One should not need to look for all edged of Hasse diagram to see that a poset is indecomposable.)
What do you mean? Your algorithm looks very reliable. I do not see it waste much.
Nathann
comment:6 in reply to: ↑ 5 ; followup: ↓ 7 Changed 5 years ago by
Replying to ncohen:
There are of course other options, like having a function (this one, with an argument?) returning list of "decomposition elements".
+1 to that.
OK. What should be the name of the argument? certificate
? give_me_the_list=True
?
How should it be defined on nonconnected posets? And I am not sure if this works with nonbounded posets; I thinked about bounded ones when writing this.
Hmmm, okay okay... I attempted to write a definition, but indeed for nonlattices you have 1000 different cornercases, and th definition would be a mess.
Except for the 2element lattice there is one simple definition that generalizes this:
any(P.cover_relations_graph().is_cut_vertex(e) for e in P)
But in any case, it is easy to move this to posets later if we want so.
(Btw, this would be nice exercise of (totally unneeded) optimization. One should not need to look for all edged of Hasse diagram to see that a poset is indecomposable.)
What do you mean? Your algorithm looks very reliable. I do not see it waste much.
If the poset has coverings 2 > 6
and 4 > 9
, then no element 3..8
can be a decomposition element. After founding, say, 2 > 6
we could check 5 >
, 4 >
and so on. But after founding 4 > 9
we should have a somewhat complicated stack to skip rechecking biggest covers of 4
and 5
. I guess that the algorithm would be slower in reality, but I am quite sure that it would be better in some theoretical meaning.
comment:7 in reply to: ↑ 6 ; followup: ↓ 10 Changed 5 years ago by
OK. What should be the name of the argument?
certificate
?give_me_the_list=True
?
Isn't there a terminology for those points? If it is only for lattices, maybe you could have return_cutvertices=True
or something?
Except for the 2element lattice there is one simple definition that generalizes this:
any(P.cover_relations_graph().is_cut_vertex(e) for e in P)
Wouldn't work for a poset on three elements, one being greater than the two others (which are incomparable).
If the poset has coverings
2 > 6
and4 > 9
, then no element3..8
can be a decomposition element. After founding, say,2 > 6
we could check5 >
,4 >
and so on. But after founding4 > 9
we should have a somewhat complicated stack to skip rechecking biggest covers of4
and5
. I guess that the algorithm would be slower in reality, but I am quite sure that it would be better in some theoretical meaning.
HMmm... Skipping some edges without additional assumption on the order in which they are returned? I do not know... This is not so bad, for the moment :)
Nathann
comment:8 Changed 5 years ago by
 Commit changed from 0d472a68c9edf4ddea1404ff0cb6d2f508de55d0 to 893ecc133183398f0932e02c146f235230784915
Branch pushed to git repo; I updated commit sha1. New commits:
893ecc1  Added an option to get "decomposing elements".

comment:9 Changed 5 years ago by
You don't have to write this algorithm twice to make it work in all situations. Once is enough. And if you are worried of the cost of a 'if' inside of the loop, then you should not be writing Python code.
Furthermore, be careful with '::' as they are not needed after an INPUT block. Build the doc to check it.
Nathann
comment:10 in reply to: ↑ 7 Changed 5 years ago by
Now it should work with empty lattice, 1element lattice and 2element lattice. There is backend ready for extending the function in lattices.py
. I may modify it as suggested by Nathann at comment 9. But the more important question:
How should we exactly define "decomposing elements"? Let's start with
Posets.ChainPoset(2).ordinal_sum(Posets.BooleanLattice(3), labels='integers')
Is 0
a decomposing element? What are "components" for the lattice? Maybe 01
, 12
and 29
. But then, what are components of 2element lattice?
Replying to ncohen:
If the poset has coverings
2 > 6
and4 > 9
, then no element3..8
can be a decomposition element. After founding, say,2 > 6
we could check5 >
,4 >
and so on. But after founding4 > 9
we should have a somewhat complicated stack to skip rechecking biggest covers of4
and5
. I guess that the algorithm would be slower in reality, but I am quite sure that it would be better in some theoretical meaning.HMmm... Skipping some edges without additional assumption on the order in which they are returned?
I dont' mean that. If the lattice has 100
elements, then 0
is the bottom and 99
is the top. If the lattice has coverings 0 > 37
, 34 > 88
and 77 > 99
, then it is not vertically decomposable. There might be faster way to find those coverings than going throught all elements. But the code would be much more complicated.
comment:11 followup: ↓ 13 Changed 5 years ago by
Could you also add to your docstring a reference toward a textbook that defines this notion?
comment:12 Changed 5 years ago by
 Commit changed from 893ecc133183398f0932e02c146f235230784915 to ca909a0c05fee489a071ff672b9f3b5392ba8158
Branch pushed to git repo; I updated commit sha1. New commits:
ca909a0  Indentation of INPUT block.

comment:13 in reply to: ↑ 11 Changed 5 years ago by
 Cc tscrim added
 Description modified (diff)
Replying to ncohen:
Could you also add to your docstring a reference toward a textbook that defines this notion?
Duh. Counting Finite Lattices by Heitzig and Reinhold defines it "  contains an element which is neither the greatest not the least element of L but comparable to every element of L." On the other hand, On the number of distributive lattices by Erné and (same) Heitzig and Reinhold says "  if it is either a singleton or the vertical sum of two nonempty posets  ", and vertical sum on two twoelement lattice by their definition is the twoelement lattice.
I select tscrim as another random victim. Travis, should we define the twoelement lattice to be vertically decomposable or indecomposable?
(Or raise OtherError("developers don't know how to define this")
? :=)
)
Quite easy one. Nathann selected as a random victim for a possible reviewer.
:=)
New commits:
Added function is_vertically_decomposable().
Spaces on empty lines.