Changes between Version 2 and Version 4 of Ticket #17445


Ignore:
Timestamp:
12/05/14 03:49:06 (5 years ago)
Author:
kcrisman
Comment:

Can you comment on some of the chain-rule type issues in #6480, then? I have to say that in particular the stuff at http://ask.sagemath.org/question/9932/how-to-substitute-a-function-within-derivatives/ and #6480 is massively confusing. Heck, let's add #7401 while we're at it.

I don't even know whether any of those things are "really" right or wrong at this point. I suppose you shouldn't be allowed to substitute in a function that "isn't there" in 6 and 7, but then why does 8 "work"? In any case, shouldn't there be an error raised if one attempts something like this when it's not "legitimate"?

# 6. Fails.
x = var('x')
f = function('f', x)
g = function('g', x)
p = f.diff()
print p.substitute_function(f, g) # Outputs "D[0](f)(x)"

# 7. Fails.
x = var('x')
f = function('f', x)
g = function('g', x)
p = f.diff()
print p.substitute_function(f(x), g(x)) # Outputs "D[0](f)(x)"

# 8. Works.
x = var('x')
f = function('f')
g = function('g')
p = f(x).diff()
print p.substitute_function(f, g) # Outputs "D[0](g)(x)"

These are very subtle differences to anyone who is not in symbolic algebra/expressions, and part of the issue is the difference between expressions and functions, no doubt. So comment:1 is a good start, but definitely only a start.

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