Changes between Initial Version and Version 1 of Ticket #17123, comment 50
 Timestamp:
 07/29/17 19:18:59 (4 years ago)
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Ticket #17123, comment 50
initial v1 15 15 You should be comparing with `binomial(n1, nk)`. These are really partitions of nk you are summing over (the first part is just for convenience, as you clamp it to k). 16 16 17 Sorry, but it makes no fucking sense to meto diverge from the (n choose k) = n(n1)...(nk+1)/k! standard for negative n as long as k >= 0. The binomial coefficients (n choose k) for a fixed k are a polynomial in n when n is nonnegative; why on earth would you want to break that?17 Sorry, but it makes no sense on earth, in heaven and in other places to diverge from the (n choose k) = n(n1)...(nk+1)/k! standard for negative n as long as k >= 0. The binomial coefficients (n choose k) for a fixed k are a polynomial in n when n is nonnegative; why on earth would you want to break that?