Opened 8 years ago
Last modified 4 years ago
#15504 new enhancement
Missing dilog(2) simplification
Reported by: | ppurka | Owned by: | |
---|---|---|---|
Priority: | major | Milestone: | sage-6.4 |
Component: | calculus | Keywords: | |
Cc: | jakobkroeker, kcrisman, rws | Merged in: | |
Authors: | Reviewers: | ||
Report Upstream: | N/A | Work issues: | |
Branch: | Commit: | ||
Dependencies: | Stopgaps: |
Description (last modified by )
From google spreadsheet which no one reads X-(
sage: integrate(log(1+x)/x,x) log(x + 1)*log(-x) + polylog(2, x + 1) sage: integrate(log(1+x)/x,x,0,1) -1/6*pi^2 + I*pi*log(2) + polylog(2, 2)
Since dilog(2) = -pi^2/4+log(2)^2/2-1/2*(log(2)+I*pi)^2
the result is simply pi^2/12
.
Change History (12)
comment:1 Changed 8 years ago by
- Description modified (diff)
comment:2 Changed 8 years ago by
comment:3 Changed 8 years ago by
- Milestone changed from sage-6.1 to sage-6.2
comment:4 Changed 7 years ago by
- Milestone changed from sage-6.2 to sage-6.3
comment:5 Changed 7 years ago by
- Milestone changed from sage-6.3 to sage-6.4
comment:6 Changed 6 years ago by
For completeness, sympy has
In [1]: integrate(log(1+x)/x) Out[1]: ⎛ ⅈ⋅π⎞ -polylog⎝2, x⋅ℯ ⎠ In [2]: integrate(log(1+x)/x,(x,0,1)) Out[2]: ⎛ ⅈ⋅π⎞ -polylog⎝2, ℯ ⎠
while Wolfram says integral (log(1+x))/x dx = -Li_2(-x)+constant
.
The sympy solution will also only be available with sympy-0.7.8 because of a missing polylog._sage_
method in earlier versions.
comment:7 Changed 5 years ago by
sage: integrate(log(1+x)/x,x,algorithm='sympy') -polylog(2, -x)
comment:8 Changed 4 years ago by
- Cc jakobkroeker kcrisman rws added
If this answer is wrong, mark it for a stopgap or even create one
comment:9 Changed 4 years ago by
as of v8.0.beta3, Maxima is correct:
sage: integrate(log(1+x)/x, x, 0, 1, algorithm='maxima') -1/6*pi^2 + I*pi*log(2) + dilog(2) sage: _.n() 0.822467033424113 sage: N(pi^2/12) 0.822467033424113
see W|A
the imaginary part vanishes because of the identity dilog(2) = -pi^2/4+log(2)^2/2-1/2*(log(2)+I*pi)^2
, which doesn't seem to be recognised.
comment:10 Changed 4 years ago by
- Description modified (diff)
- Summary changed from Possible integration error to Missing dilog(2) simplification
- Type changed from defect to enhancement
So I think we can at least relabel this. As the answer is correct it becomes a mere enhancement ticket.
comment:11 follow-up: ↓ 12 Changed 4 years ago by
What does giac
do, out of curiosity?
comment:12 in reply to: ↑ 11 Changed 4 years ago by
Replying to kcrisman:
What does
giac
do, out of curiosity?
- giac returns unevaluated
- sympy returns the correct + reduced answer
.. it's quite fun. in that list in github i started to evaluate the integral tickets with different algorithms.
Apparently in Maxima.