Opened 10 years ago
Last modified 5 years ago
#14092 new defect
Error with supposedly normal DE problem
Reported by: | Karl-Dieter Crisman | Owned by: | Burcin Erocal |
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Priority: | major | Milestone: | sage-6.4 |
Component: | calculus | Keywords: | |
Cc: | Stan Schymanski | Merged in: | |
Authors: | Reviewers: | ||
Report Upstream: | N/A | Work issues: | |
Branch: | Commit: | ||
Dependencies: | Stopgaps: |
Description
See this ask.sagemath.org question.
var('a b n k t') c = function('c',t) de = diff(c,t) - a + (b*c)*((c**n)/((k**n)+(c**n))) == 0 des = desolve(de,[c,t],[0,0])
yields an error about c(t) not being a proper Python identifier. Various other combinations yield similar ECL errors, and at least sometimes one can get segmentation faults after inserting print statements.
Change History (8)
comment:1 Changed 10 years ago by
comment:2 Changed 10 years ago by
I don't think it is about the number of variables, but about maxima not being able to provide an explicit solution. Here is the example computed directly in maxima:
maxima("de: 'diff(c(t),t) - a + c(t)^n") maxima("atvalue (c(t), t = 0, 0);") maxima("ode2(de,c(t),t);")
gives:
-'integrate(1/(c(t)^ n-a),c(t))=t+%c
Note that the integral containing c(t)^{n} could not be solved. Replacing n by an integer and defining c as positive:
maxima("de: 'diff(c(t),t) - a + c(t)^2") maxima("atvalue (c(t), t = 0, 0);") maxima("assume(a>0);") maxima("ode2(de,c(t),t);")
gives:
-log(-(sqrt(a)-c(t))/(c(t)+sqrt(a)))/(2*sqrt(a))=t+%c
Is it possible that the 'integrate in the solution creates a problem?
comment:3 Changed 10 years ago by
Cc: | Stan Schymanski added |
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comment:4 Changed 9 years ago by
Milestone: | sage-5.11 → sage-5.12 |
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comment:5 Changed 9 years ago by
Milestone: | sage-6.1 → sage-6.2 |
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comment:6 Changed 9 years ago by
Milestone: | sage-6.2 → sage-6.3 |
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comment:7 Changed 8 years ago by
Milestone: | sage-6.3 → sage-6.4 |
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comment:8 Changed 5 years ago by
With #22024 we get:
sage: solve(de,t,algorithm='sympy') ConditionSet(t, Eq(-a*(k**n + c(t)**n) + b*c(t)*c(t)**n + (k**n + c(t)**n)*Derivative(c(t), t), 0), Complexes(S.Reals x S.Reals, False)) \ ConditionSet(t, Eq(k**n + c(t)**n, 0), Complexes(S.Reals x S.Reals, False))
Simpler example that seems to behave analogously.
Note that making
n
a specific integer gives questions about the sign ofa
andassume(a>0)
fixes things.Are there maybe just too many variables?